Apolonio_LLC _escala_=37.274441711616 _Ox_=-119 _Oy_=22 _nNOG_=62 _pasos_=1 'P_101:=newCnstrGCtrl('','',-6.245063191153238,-3.060821484992101,'',gris_descartes,2,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2 ¦ '' ¦ '' ¦ 0 'P_102:=newCnstrGCtrl('','',9.75019747235387,-3.1166215435977227,'',gris_descartes,2,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2 ¦ '' ¦ '' ¦ 0 'P_103:=newCnstrGCtrl('','',2.3449842022116902,4.8627567140600325,'',gris_descartes,2,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2 ¦ '' ¦ '' ¦ 0 'L_106:=newLine2D(P_101,P_103,fuerte,2,'(ver>=0)')' ¦ 'fuerte' ¦ 2 ¦ '' ¦ '' ¦ 0 'L_109:=newLine2D(P_101,P_102,fuerte,2,'(ver>=0)')' ¦ 'fuerte' ¦ 2 ¦ '' ¦ '' ¦ 0 'P_110:=newCnstrGCtrl('','',3.6178345521396564,-0.9186414530610945,'',fuerte,2,'(ver>=0)')' ¦ 'fuerte' ¦ 2 ¦ '' ¦ '' ¦ 0 'P_111:=newCnstrGCtrl('','',-7.026601916089306,-5.347974273371287,'',gris_descartes,2.5,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_112:=newCnstrGCtrl('','',-8.018082713304922,-5.374802307651094,'',gris_descartes,2.5,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'L_115:=newS(P_111,P_112,gris_descartes,2,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2 ¦ '' ¦ '' ¦ 0 'C_116:=newCircleSC2D(L_115,P_110,fuerte,2,'(ver>=0)')' ¦ 'fuerte' ¦ 2 ¦ '' ¦ '' ¦ 0 'L_119:=newPerp2D(L_109,P_110,gris_descartes,2,'(ver>=0)')' ¦ 'gris_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'L_122:=newPerp2D(L_106,P_110,gris_descartes,1,'(ver>=0)')' ¦ 'gris_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_123:=newMeetLL2D('','',L_109,L_119,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_124:=newMeetLL2D('','',L_106,L_122,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'C_125:=newCircleSC2D(L_115,P_123,gris_descartes,1,'(ver>=0)')' ¦ 'gris_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'C_126:=newCircleSC2D(L_115,P_124,gris_descartes,1,'(ver>=0)')' ¦ 'gris_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_127:=newFirstMeetLC2D('','',L_122,C_126,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_128:=newSecondMeetLC2D('','',L_122,C_126,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_129:=newFirstMeetLC2D('','',L_119,C_125,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_130:=newSecondMeetLC2D('','',L_119,C_125,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'L_133:=newParal2D(L_106,P_127,rosa,2,'(ver>=0)')' ¦ 'rosa' ¦ 2 ¦ '' ¦ '' ¦ 0 'L_136:=newParal2D(L_109,P_130,rosa,2,'(ver>=0)')' ¦ 'rosa' ¦ 2 ¦ '' ¦ '' ¦ 0 'P_137:=newMeetLL2D('','',L_133,L_136,'(ver>=0)')' ¦ 'rosa' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'L_140:=newBisector2D(P_137,P_130,P_127,azul_descartes,2,'(ver>=0)')' ¦ 'gris_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'L_143:=newPerp2D(L_140,P_110,azul_descartes,1,'(ver>=0)')' ¦ 'gris_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_144:=newMeetLL2D('','',L_136,L_143,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_145:=newMidPoint('','',P_137,P_144,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'C_146:=newCircleCP2D(P_145,P_137,azul_descartes,1,'(ver>=0)')' ¦ 'azul_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'C_147:=newCircleCP2D(P_137,P_110,azul_descartes,1,'(ver>=0)')' ¦ 'azul_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_155:=newFirstMeetCC2D('','',C_146,C_147,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_163:=newSecondMeetCC2D('','',C_146,C_147,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'C_164:=newCircleCP2D(P_144,P_163,azul_descartes,1,'(ver>=0)')' ¦ 'azul_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_165:=newFirstMeetLC2D('','',L_136,C_164,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_166:=newSecondMeetLC2D('','',L_136,C_164,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'L_169:=newPerp2D(L_136,P_165,azul_descartes,1,'(ver>=0)')' ¦ 'azul_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'L_172:=newPerp2D(L_136,P_166,azul_descartes,1,'(ver>=0)')' ¦ 'azul_descartes' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_173:=newMeetLL2D('','',L_140,L_169,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_174:=newMeetLL2D('','',L_140,L_172,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_175:=newFootLP2D('','',L_106,P_173,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_176:=newFootLP2D('','',L_106,P_174,'(ver>=0)')' ¦ 'azul_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'C_177:=newCircleCP2D(P_173,P_175,rojo,2,'(ver>=0)')' ¦ 'rojo' ¦ 2 ¦ '' ¦ '' ¦ 0 'C_178:=newCircleCP2D(P_174,P_176,rojo,2,'(ver>=0)')' ¦ 'rojo' ¦ 2 ¦ '' ¦ '' ¦ 0 'L_181:=newParal2D(L_109,P_129,naranja,2,'(ver>=0)')' ¦ 'naranja' ¦ 1 ¦ '' ¦ '' ¦ 0 'L_184:=newParal2D(L_106,P_128,fuerte,2,'(ver>=0)')' ¦ 'naranja' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_185:=newMeetLL2D('','',L_181,L_184,'(ver>=0)')' ¦ 'naranja' ¦ 3 ¦ '' ¦ '' ¦ 0 'P_186:=newMeetLL2D('','',L_143,L_181,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_187:=newMidPoint('','',P_185,P_186,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'C_188:=newCircleCP2D(P_187,P_185,verde,1,'(ver>=0)')' ¦ 'verde' ¦ 1 ¦ '' ¦ '' ¦ 0 'C_189:=newCircleCP2D(P_185,P_110,verde,1,'(ver>=0)')' ¦ 'verde' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_197:=newFirstMeetCC2D('','',C_188,C_189,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_205:=newSecondMeetCC2D('','',C_188,C_189,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'C_206:=newCircleCP2D(P_186,P_205,verde,1,'(ver>=0)')' ¦ 'verde' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_207:=newFirstMeetLC2D('','',L_181,C_206,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_208:=newSecondMeetLC2D('','',L_181,C_206,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'L_211:=newPerp2D(L_181,P_208,verde,1,'(ver>=0)')' ¦ 'verde' ¦ 1 ¦ '' ¦ '' ¦ 0 'L_214:=newPerp2D(L_181,P_207,verde,1,'(ver>=0)')' ¦ 'verde' ¦ 1 ¦ '' ¦ '' ¦ 0 'P_215:=newMeetLL2D('','',L_140,L_214,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_216:=newMeetLL2D('','',L_140,L_211,'(ver>=0)')' ¦ 'gris_descartes' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_217:=newFootLP2D('','',L_109,P_215,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'P_218:=newFootLP2D('','',L_109,P_216,'(ver>=0)')' ¦ 'verde' ¦ 2.5 ¦ '' ¦ '' ¦ 0 'C_219:=newCircleCP2D(P_215,P_217,rojo,2,'(ver>=0)')' ¦ 'turquesa' ¦ 2 ¦ '' ¦ '' ¦ 0 'C_220:=newCircleCP2D(P_216,P_218,rojo,2,'(ver>=0)')' ¦ 'turquesa' ¦ 2 ¦ '' ¦ '' ¦ 0 'C_220' ¦ 'Este caso se reduce al PLL mediante traslaciones de las rectas por el radio de la circunferencia. Si se trasladan hacia afuera se obtiene círculos tangentes (ROJOS) que no contiene al círculo dado, en caso contrario se obtiene círculos (TURQUESA) que sí lo contienen. Hay 4 soluciones, aunque aquí solo vemos las que corresponden a las construcciones basadas en una de las bisectrices. Si se hicieran las construcciones correspondientes a la otra bisectriz, podrían verse siempre las cuatro soluciones.' 1 ¦ 0 ¦ 1 ¦ 0 ¦ 1 ¦ 0 ¦ 1 ¦ 0 ¦ 1 ¦ 0